Chemistry · 2022
JEE Main · 25 July 2022, Shift 2 · Q63
K_a_1, K_a_2 and K_a_3 are the respective ionization constants for the following reactions (a), (b), and (c). (a) H_2 C_2 O_4= H^++ HC_2 O_4^- (b)…
$\displaystyle \mathrm{K}_{\mathrm{a}_1}, \mathrm{~K}_{\mathrm{a}_2}$ and $\displaystyle \mathrm{K}_{\mathrm{a}_3}$ are the respective ionization constants for the following reactions (a), (b), and (c).
(a)
$\displaystyle \mathrm{H}_2 \mathrm{C}_2 \mathrm{O}_4=\mathrm{H}^{+}+\mathrm{HC}_2 \mathrm{O}_4^{-}$
(b)
$\displaystyle \mathrm{HC}_2 \mathrm{O}_4^{-}=\mathrm{H}^{+}+\mathrm{HC}_2 \mathrm{O}_4^{2-}$
(c)
$\displaystyle \mathrm{H}_2 \mathrm{C}_2 \mathrm{O}_4=2 \mathrm{H}^{+}+\mathrm{C}_2 \mathrm{O}_4^{2-}$
The relationship between $\displaystyle \mathrm{K}_{\mathrm{a}_1}, \mathrm{~K}_{\mathrm{a}_2}$ and $\displaystyle \mathrm{K}_{\mathrm{a}_3}$ is given as
Official answer
(4)
$\displaystyle K_{a_3}=K_{a_1} \times K_{a_2}$
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JEE Main 2022 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.