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Chemistry · 2026

JEE Main · 6 April 2026, Shift 2 · Q72

An alkane ( Y ) requires 8 moles of oxygen for complete combustion and on chlorination with Cl_2 / h ν,( Y ) gives only one monochlorinated product…

An alkane $\displaystyle (\mathrm{Y})$ requires $\displaystyle 8$ moles of oxygen for complete combustion and on chlorination with $\displaystyle \mathrm{Cl}_2 / \mathrm{h} \nu,(\mathrm{Y})$ gives only one monochlorinated product (Z). The total number of primary carbon atoms in $\displaystyle (Y)$ is $\displaystyle \_\_\_\_$.
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JEE Main 2026 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.