Chemistry · 2017
JEE Main · 9 April 2017, Shift 1 · Q38
Adsorption of a gas on a surface follows Freundlich adsorption isotherm. Plot of log x/m versus log p gives a straight line with slope equal to 0.5,…
Adsorption of a gas on a surface follows Freundlich adsorption isotherm. Plot of $\displaystyle \log \frac{x}{\mathrm{~m}}$ versus $\displaystyle \log \mathrm{p}$ gives a straight line with slope equal to $\displaystyle 0.5$, then :
( $\displaystyle \frac{x}{\mathrm{~m}}$ is the mass of the gas adsorbed per gram of adsorbent)
Official answer
(3)
Adsorption is proportional to the square root of pressure.
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JEE Main 2017 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.