Chemistry · 2022
JEE Main · 28 June 2022, Shift 2 · Q64
A student needs to prepare a buffer solution of propanoic acid and its sodium salt with pH 4. The ratio of ([ CH_3 CH_2 COO^-])/([ CH_3 CH_2 COOH ])…
A student needs to prepare a buffer solution of propanoic acid and its sodium salt with pH $\displaystyle 4$ .
The ratio of $\displaystyle \frac{\left[\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{COO}^{-}\right]}{\left[\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{COOH}\right]}$ required to make buffer is \_\_\_\_.Given : $\displaystyle \mathrm{K}_{\mathrm{a}}\left(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{COOH}\right)=1.3 \times 10^{-5}$
Official answer
(2)
$\displaystyle 0.13$
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JEE Main 2022 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.