Chemistry · 2026
JEE Main · 24 January 2026, Shift 1 · Q54
A solution is prepared by dissolving 0.3 g of a non-volatile non-electrolyte solute 'A' of molar mass 60 g mol^-1 and 0.9 g of a non-volatile…
A solution is prepared by dissolving $\displaystyle 0.3$ g of a non-volatile non-electrolyte solute 'A' of molar mass $\displaystyle 60 \mathrm{~g} \mathrm{~mol}^{-1}$ and $\displaystyle 0.9$ g of a non-volatile non-electrolyte solute 'B' of molar mass $\displaystyle 180 \mathrm{~g} \mathrm{~mol}^{-1}$ in $\displaystyle 100 \mathrm{~mL} \mathrm{H}_2 \mathrm{O}$ at $\displaystyle 27^{\circ} \mathrm{C}$. Osmotic pressure of the solution will be
[Given: $\displaystyle \mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$ ]
Official answer
From NTA’s final answer key for this paper.
(3)
2.$\displaystyle 46$ atm
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JEE Main 2026 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.