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Chemistry · 2026

JEE Main · 22 January 2026, Shift 1 · Q61

A first row transition metal (M) does not liberate H_2 gas from dilute HCl. 1 mol of aqueous solution of MSO_4 is treated with excess of aqueous KCN…

A first row transition metal (M) does not liberate $\displaystyle \mathrm{H}_2$ gas from dilute HCl. $\displaystyle 1$ mol of aqueous solution of $\displaystyle \mathrm{MSO}_4$ is treated with excess of aqueous KCN and then $\displaystyle \mathrm{H}_2 \mathrm{~S}(\mathrm{~g})$ is passed through the solution. The amount of MS (metal sulphide) formed from the above reaction is $\displaystyle \_\_\_\_$ mol .
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JEE Main 2026 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.