Chemistry · 2022
JEE Main · 29 July 2022, Shift 2 · Q64
200 mL of 0.01 M HCl is mixed with 400 mL of 0.01 M H_2 SO_4. The pH of the mixture is \ \ \ \. Given: log 2=0.30, log 3=0.48, log 5=0.70, log…
$\displaystyle 200$ mL of $\displaystyle 0.01$ M HCl is mixed with $\displaystyle 400$ mL of $\displaystyle 0.01 \mathrm{M} \mathrm{H}_2 \mathrm{SO}_4$. The pH of the mixture is \_\_\_\_.
Given: $\displaystyle \log 2=0.30, \log 3=0.48, \log 5=0.70, \log 7=0.84, \log 11=1.04$
Official answer
(2)
$\displaystyle 1.78$
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JEE Main 2022 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.