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Chemistry · 2019
JEE Main · 9 January 2019, Shift 1 · Q57
20 mL of 0.1 M H_2 SO_4 solution is added to 30 mL of 0.2 M NH_4 OH solution. The pH of the resultant mixture is: [ pk_b. of NH_4 OH =4.7 ].
$\displaystyle 20$ mL of $\displaystyle 0.1 \mathrm{M} \mathrm{H}_2 \mathrm{SO}_4$ solution is added to $\displaystyle 30$ mL of $\displaystyle 0.2 \mathrm{M} \mathrm{NH}_4 \mathrm{OH}$ solution. The pH of the resultant mixture is : $\displaystyle \left[\mathrm{pk}_{\mathrm{b}}\right.$ of $\displaystyle \mathrm{NH}_4 \mathrm{OH}=4.7$ ].
Official answer
(3)
$\displaystyle 9.0$
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JEE Main 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.