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Chemistry · 2022

JEE Main · 26 July 2022, Shift 2 · Q85

20 mL of 0.02 M hypo solution is used for the titration of 10 mL of copper sulphate solution, in the presence of excess of KI using starch as an…

$\displaystyle 20$ mL of $\displaystyle 0.02$ M hypo solution is used for the titration of $\displaystyle 10$ mL of copper sulphate solution, in the presence of excess of KI using starch as an indicator. The molarity of $\displaystyle \mathrm{Cu}^{2+}$ is found to be \_\_\_\_ $\displaystyle \times 10^{-2} \mathrm{M}$. [nearest integer] Given : $\displaystyle 2 \mathrm{Cu}^{2+}+4 \mathrm{I}^{-} \rightarrow \mathrm{Cu}_2 \mathrm{I}_2+\mathrm{I}_2$ $$\mathrm{I}_2+2 \mathrm{~S}_2 \mathrm{O}_3^{2-} \rightarrow 2 \mathrm{I}^{-}+\mathrm{S}_4 \mathrm{O}_6^{2-} $$
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JEE Main 2022 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.