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Chemistry · 2021

JEE Main · 27 July 2021, Shift 2 · Q60

0 mL of 0.05 M KMnO_4 solution was consumed in a titration with 10.0 mL of given oxalic acid dihydrate solution. The strength of given oxalic acid…

$\displaystyle 0$ mL of $\displaystyle 0.05 \mathrm{M} \mathrm{KMnO}_4$ solution was consumed in a titration with $\displaystyle 10.0$ mL of given oxalic acid dihydrate solution. The strength of given oxalic acid solution is \_\_\_\_ $\displaystyle \times 10^{-2} \mathrm{~g} / \mathrm{L}$. (Round off to the Nearest Integer).
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JEE Main 2021 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.