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Physics · 2026 · 2 marks
Ray Optics and Optical InstrumentsRefraction at Spherical Surfaces and by Lenses2 marksApplyvery short answer
CBSE 2026 · Region 5 · Set 1 · Q20
Two thin lenses of focal length f_1 and f_2 are placed in contact with each other coaxially. Prove that the focal length f of the combination is…
Two thin lenses of focal length $\displaystyle \mathrm{f}_{1}$ and $\displaystyle \mathrm{f}_{2}$ are placed in contact with each other coaxially. Prove that the focal length f of the combination is given by $\displaystyle \mathrm{f}=\frac{\mathrm{f}_{1} \mathrm{f}_{2}}{\mathrm{f}_{1}+\mathrm{f}_{2}}$.
Marking-scheme solution
Proving the focal length of combination is $\displaystyle \mathrm{f}=\frac{\mathrm{f}_{1} \mathrm{f}_{2}}{\mathrm{f}_{1}+\mathrm{f}_{2}}$ $\displaystyle 2$
\[\xrightarrow[\mathrm{O}]{ }
\]
For the image formed by lens A
\[\frac{1}{\mathrm{v}_{1}}-\frac{1}{u}=\frac{1}{\mathrm{f}_{1}}
\]
For the image formed by second lens B
\[\frac{1}{\mathrm{v}}-\frac{1}{\mathrm{v}_{1}}=\frac{1}{\mathrm{f}_{2}}
\]
Adding (i)and(ii)
\[\begin{aligned}
& \frac{1}{\mathrm{v}}-\frac{1}{u}=\frac{1}{\mathrm{f}_{2}}+\frac{1}{\mathrm{f}_{1}} \\
& \frac{1}{\mathrm{f}}=\frac{1}{\mathrm{f}_{1}}+\frac{1}{\mathrm{f}_{2}} \\
& \mathrm{f}=\frac{\mathrm{f}_{1} \mathrm{f}_{2}}{\mathrm{f}_{1}+\mathrm{f}_{2}}
\end{aligned}
\]
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