Two concave lenses A and B, each of focal length 8.0 cm are arranged coaxially 16 cm apart as shown in figure. An object P is placed at a distance of…

For the first lens: $\displaystyle \frac{1}{v_{1}}-\frac{1}{u_{1}}=\frac{1}{f_{1}}$ $\displaystyle \frac{1}{v_{1}}+\frac{1}{4}=-\frac{1}{8}$ $\displaystyle v_{1}=-\frac{8}{3} \mathrm{~cm}$ For the second lens: $\displaystyle u_{2}=-16-\frac{8}{3}=-\frac{56}{3} \mathrm{~cm}$ $\displaystyle \frac{1}{v_{2}}-\left(-\frac{3}{56}\right)=-\frac{1}{8}$ $\displaystyle v_{2}=-5.6 \mathrm{~cm}$ Image is virtual.