The magnifying power of an astronomical telescope is 24. In normal adjustment, distance between its two lenses is 150 cm. Find the focal length of…

Magnifying power = $\displaystyle 24$ , Distance between lenses =$\displaystyle 150$ cm \[\frac{f_{o}}{f_{e}}=24 \] \(\displaystyle f_{o}+f_{e}=150 \mathrm{~cm}\) \(\displaystyle f_{e}=6 \mathrm{~cm}\) \(\displaystyle f_{o}=144 \mathrm{~cm}\)