An object is placed 30 cm in front of a concave mirror of radius of curvature 40 cm. Find the (i) position of the image formed and (ii) magnification…

\[\begin{aligned} & \text { (i) } \frac{1}{\mathrm{v}}+\frac{1}{u}=\frac{1}{f} \\ & \frac{1}{\mathrm{v}}+\frac{1}{-30}=\frac{1}{-20} \end{aligned} \] On solving \[\mathrm{v}=-60 \mathrm{~cm} \]