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Physics · 2024 · 2 marks
CBSE 2024 · Region 5 · Set 1 · Q19
A telescope has an objective lens of focal length 150 cm and an eyepiece of focal length 5 cm. Calculate its magnifying power in normal adjustment…
A telescope has an objective lens of focal length $\displaystyle 150$ cm and an eyepiece of focal length $\displaystyle 5$ cm . Calculate its magnifying power in normal adjustment and the distance of the image formed by the objective.
Marking-scheme solution
$\displaystyle m=\frac{f_{0}}{f_{e}}$
$\displaystyle =\frac{150}{5}=30$
$\displaystyle \frac{1}{f}=\frac{1}{v}-\frac{1}{u}$
$\displaystyle \frac{1}{150}=\frac{1}{v}-\frac{1}{\infty}$
$\displaystyle v=150 \mathrm{~cm}$
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