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Physics · 2023 · 3 marks
CBSE 2023 · Region 2 · Set 3 · Q26
A ray of light is refracted by a glass prism. Obtain an expression for the refractive index of the glass in terms of the angle of prism A and the…
A ray of light is refracted by a glass prism. Obtain an expression for the refractive index of the glass in terms of the angle of prism A and the angle of minimum deviation $\displaystyle \delta \mathrm{m}$.
Marking-scheme solution
Obtaining expression
\[\mu=\frac{\sin \left(\dfrac{A+\delta_{\mathrm{m}}}{2}\right)}{\sin \left(\dfrac{A}{2}\right)}
\] At minimum deviation, a ray of light passes through a prism symmetrically i.e \(\displaystyle \angle i=\angle e, \angle r_{1}=\angle r_{2}=\angle r\) We know that \(\displaystyle i+e=A+\delta \quad\) and \(\displaystyle r_{1}+r_{2}=A\)
\[\begin{aligned}
\therefore \quad & i+i=A+\delta \mathrm{m} \\
& i=\frac{A+\delta \mathrm{m}}{2}
\end{aligned}
\] And also
\[\begin{aligned}
& r+r=A \\
\Rightarrow & r=\frac{A}{2}
\end{aligned}
\] Using Snell's law
\[\begin{aligned}
& \mu=\frac{\sin i}{\sin r} \\
& \mu=\frac{\sin \left(\dfrac{A+\delta \mathrm{m}}{2}\right)}{\sin \left(\dfrac{A}{2}\right)}
\end{aligned}
\]
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