A point source in air is kept 24 cm in front of a concave spherical glass surface ( a μ g=1.5) and radius of curvature 60 cm. Find the nature of the…

Relation for concave spherical surface (μ 1)/-u+(μ 2)/v=(μ 2-μ 1)/R 1/-u+(μ)/( v )=(μ-1)/R 1/(-(-24))+(1 · 5)/v=(1 · 5-1)/-60 v =-30 cm Distance of image from point source =-24-(-30)=6 cm Nature of image = Virtual image

CBSE 2022 · Region 1 · Set 1 · Q5 · 3 marks

A point source in air is kept $\displaystyle 24$ cm in front of a concave spherical glass surface $\displaystyle \left({ }_{\mathrm{a}} \mu_{\mathrm{g}}=1.5\right)$ and radius of curvature $\displaystyle 60$ cm. Find the nature of the image formed and its distance from the point source.

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A point source in air is kept $\displaystyle 24$ cm in front of a concave spherical glass surface $\displaystyle \left({ }_{\mathrm{a}} \mu_{\mathrm{g}}=1.5\right)$ and radius of curvature $\displaystyle 60$ cm. Find the nature of the image formed and its distance from the point source.

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