A point source in air is kept 24 cm in front of a concave spherical glass surface (_a μ_g =1.5) and radius of curvature 60 cm. Find the nature of the…

Relation for concave spherical surface $$\frac{\mu_{1}}{-u}+\frac{\mu_{2}}{v}=\frac{\mu_{2}-\mu_{1}}{R} $$ $\displaystyle \frac{1}{-u}+\frac{\mu}{\mathrm{v}}=\frac{\mu-1}{R}$ $$\frac{1}{-(-24)}+\frac{1 \cdot 5}{v}=\frac{1 \cdot 5-1}{-60} $$ $\displaystyle \therefore \mathrm{v}=-30 \mathrm{~cm}$ Distance of image from point source $\displaystyle =-24-(-30)=6 \mathrm{~cm}$ Nature of image = Virtual image