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Mathematics · 2024 · 1 mark
CBSE 2024 · Region 4 · Set 1 · Q15
The lines (1-x)/2=(y -1)/3=z/1 and (2 x-3)/(2 p)=y/-1=(z -4)/7 are perpendicular to each other for p equal to:
The lines $\displaystyle \frac{1-x}{2}=\frac{\mathrm{y}-1}{3}=\frac{\mathrm{z}}{1}$ and $\displaystyle \frac{2 x-3}{2 \mathrm{p}}=\frac{\mathrm{y}}{-1}=\frac{\mathrm{z}-4}{7}$ are perpendicular to each other for p equal to:
Official answer
(C)
$\displaystyle 2$
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