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Mathematics · 2026 · 1 mark
CBSE 2026 · Region 1 · Set 2 · Q18
The absolute maximum value of f (x)=x^2+1 in [-5,2] is
The absolute maximum value of $\displaystyle \mathrm{f}(x)=x^{2}+1$ in $\displaystyle [-5,2]$ is
Official answer
(A)
$\displaystyle 26$
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