CBSE 2024 · Region 3 · Set 1 · Q11 · 1 mark
Let E and F be two events such that $\displaystyle \mathrm{P}(\mathrm{E})=0 \cdot 1, \mathrm{P}(\mathrm{F})=0 \cdot 3, \mathrm{P}(\mathrm{E} \cup \mathrm{F})=0 \cdot 4$, then $\displaystyle \mathrm{P}(\mathrm{F} \mid \mathrm{E})$ is :
Official answer
From CBSE’s own marking scheme for this paper.
(D)
$\displaystyle 0$
ProbabilityConditional ProbabilityApplymcqmedium
More from Probability
- Assertion: Two coins are tossed simultaneously. The probability of getting two heads, if it is known that at…2023 · asked 3×
- A shop selling electronic items sells smartphones of only three reputed companies A, B and C because chances…2025 · asked 3×
- Smoking increases the risk of lung problems. A study revealed that 170 in 1000 males who smoke develop lung…2026 · asked 3×
- The probability distribution of a random variable X is: where k is some unknown constant. The probability…2024 · asked 3×
- Recent studies suggest that roughly 12 % of the world population is left handed. Depending upon the parents,…2023 · asked 3×
- Two balls are drawn at random from a bag containing 2 red balls and 3 blue balls, without replacement. Let…2022 · asked 3×
- Let X be a random variable which assumes values x 1, x 2, x 3, x 4 such that 2 P(X=x 1)=3 P(X=x 2)=P(X=x 3)=5…2022 · asked 3×
- The probability distribution of a random variable X is given below: (i) Find the value of k. (ii) Find P(1 ≤…2023 · asked 3×
CBSE Class 12 Mathematics past-paper question from the 2024board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.