✓ Board-verified
Mathematics · 2026 · 1 mark
CBSE 2026 · Region 4 · Set 2 · Q2
Let A =[ a_ij ] be a 2 × 2 matrix whose elements are given by a_ij =((2 i - j )^2)/3. Then A^′ is:
Let $\displaystyle \mathrm{A}=\left[\mathrm{a}_{\mathrm{ij}}\right]$ be a $\displaystyle 2 \times 2$ matrix whose elements are given by $\displaystyle \mathrm{a}_{\mathrm{ij}}=\frac{(2 \mathrm{i}-\mathrm{j})^{2}}{3}$. Then $\displaystyle \mathrm{A}^{\prime}$ is :
Official answer
(A)
$\displaystyle \left[\begin{array}{cc}\frac{1}{3} & 3 \\ 0 & \frac{4}{3}\end{array}\right]$
More from Matrices
- Let both AB^′ and B^′ A be defined for matrices A and B. If order of A is n × m, then the order of B is:2025
- Given A= [-4, 4, 4; -7, 1, 3; 5, -3, -1] and B= [1, -1, 1; 1, -2, -2; 2, 1, 3], find AB. Hence, solve the system of linear equations: x-y+z=4; x-2…2025
- If a matrix A is both symmetric and skew-symmetric, then A is a:2025
- If A= [x, 0; 1, 1] and B= [4, 0; -1, 1], then value of x for which A^2=B is:2024
- If A= [1, 2, 3; 3, -2, 1; 4, 2, 1], then show that A^3-23 A-40 I=O.2023
- If [x, 2, 0] [5; -1; x] = [3, 1] [-2; x], then value of x is:2024
- If A= [0, -3, 8; 3, 0, 5; -8, -5, 0], then A is a:2025
- Four friends Abhay, Bina, Chhaya and Devesh were asked to simplify 4 AB+3(AB+BA)-4 BA, where A and B are both matrices of order 2 × 2. It is known…2025
CBSE Class 12 Mathematics past-paper question from the 2026 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.