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Mathematics · 2023 · 1 mark

CBSE 2023 · Region 4 · Set 2 · Q1

If [1, 1, 1; 0, 1, 1; 0, 0, 1] [x; y; z] = [6; 3; 2], then the value of (2 x+y-z) is:

If $\displaystyle \left[\begin{array}{lll}1 & 1 & 1 \\ 0 & 1 & 1 \\ 0 & 0 & 1\end{array}\right]\left[\begin{array}{l}x \\ y \\ z\end{array}\right]=\left[\begin{array}{l}6 \\ 3 \\ 2\end{array}\right]$, then the value of $\displaystyle (2 x+y-z)$ is :
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