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Mathematics · 2025 · 1 mark

CBSE 2025 · Region 7 · Set 1 · Q7

If [2 x -1, 3 x; 0, y^2-1] = [x +3, 12; 0, 35], then the value of ( x - y ) is:

If $\displaystyle \left[\begin{array}{cc}2 \mathrm{x}-1 & 3 \mathrm{x} \\ 0 & \mathrm{y}^{2}-1\end{array}\right]=\left[\begin{array}{cc}\mathrm{x}+3 & 12 \\ 0 & 35\end{array}\right]$, then the value of $\displaystyle (\mathrm{x}-\mathrm{y})$ is :
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