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CBSE 2025 · Region 7 · Set 1 · Q17 · 1 mark

If $\displaystyle \mathrm{P}(\mathrm{A})=\frac{1}{7}, \mathrm{P}(\mathrm{B})=\frac{5}{7}$ and $\displaystyle \mathrm{P}(\mathrm{A} \cap \mathrm{B})=\frac{4}{7}$, then $\displaystyle \mathrm{P}(\overline{\mathrm{A}} \mid \mathrm{B})$ is :

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