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Mathematics · 2024 · 5 marks
CBSE 2024 · Region 2 · Set 2 · Q32
Find the value of p for which the lines r =λ i +(2 λ+1) j +(3 λ+2) k and r = i -3 μ j +(p μ+7) k are perpendicular to each other and also intersect.…
Find the value of $\displaystyle p$ for which the lines \[\begin{aligned} & \vec{r}=\lambda \hat{i}+(2 \lambda+1) \hat{j}+(3 \lambda+2) \hat{k} \text { and } \\ & \vec{r}=\hat{i}-3 \mu \hat{j}+(p \mu+7) \hat{k} \end{aligned} \] are perpendicular to each other and also intersect. Also, find the point of intersection of the given lines.
Marking-scheme solution
Given lines are
$$\begin{aligned}
& \vec{r}=\hat{\jmath}+2 \hat{k}+\lambda(\hat{\imath}+2 \hat{\jmath}+3 \hat{k}) \text { and } \\
& \vec{r}=\hat{\imath}+7 \hat{k}+\mu(-3 \hat{\jmath}+p \hat{k})
\end{aligned}
$$
The lines are perpendicular
$$(\hat{\imath}+2 \hat{\jmath}+3 \hat{k}) \cdot(-3 \hat{\jmath}+p \hat{k})=0 \Rightarrow-6+3 p=0 \Rightarrow p=2
$$
The coordinates of any point on the two lines are
$$(\lambda, 2 \lambda+1,3 \lambda+2) \text { and }(1,-3 \mu, 2 \mu+7)
$$
For the point of intersection, we must have
$\displaystyle \lambda=1,2 \lambda+1=-3 \mu, 3 \lambda+2=2 \mu+7$ for some $\displaystyle \lambda$ and $\displaystyle \mu$.
Solving first two equations, we get, $\displaystyle \lambda=1, \mu=-1$, which satisfies the third equation as $\displaystyle 5=5$ is true.
Hence, the lines intersect each other.
The Point of intersection is ( $\displaystyle 1,3,5$ )
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CBSE Class 12 Mathematics past-paper question from the 2024 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.