CBSE 2023 · Region 4 · Set 1 · Q23 · 2 marks
Find the maximum and minimum values of the function given by $\displaystyle \mathrm{f}(\mathrm{x})=5+\sin 2 \mathrm{x}$.
Marking-scheme solution
We know that $\displaystyle -1 \leq \sin 2 \mathrm{x} \leq 1$\begin{aligned}
& \Rightarrow 4 \leq \sin 2 \mathrm{x}+5 \leq 1+5
& \Rightarrow 4 \leq \sin 2 \mathrm{x}+5 \leq 6
\end{aligned}So, maximum value is $\displaystyle 6$ and minimum value is $\displaystyle 4$
Application of DerivativesMaxima and MinimaApplyvery_short_answereasy
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CBSE Class 12 Mathematics past-paper question from the 2023board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.