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Mathematics · 2024 · 5 marks
CBSE 2024 · Region 3 · Set 1 · Q35
(a) Find the equation of the line passing through the point of intersection of the lines x/1=(y -1)/2=(z -2)/3 and (x -1)/0=y/-3=(z -7)/2 and…
Find the equation of the line passing through the point of intersection of the lines $\displaystyle \frac{\mathrm{x}}{1}=\frac{\mathrm{y}-1}{2}=\frac{\mathrm{z}-2}{3}$ and $\displaystyle \frac{\mathrm{x}-1}{0}=\frac{\mathrm{y}}{-3}=\frac{\mathrm{z}-7}{2}$ and perpendicular to these given lines.
Two vertices of the parallelogram ABCD are given as $\displaystyle \mathrm{A}(-1,2,1)$ and $\displaystyle \mathrm{B}(1,-2,5)$. If the equation of the line passing through C and D is $\displaystyle \frac{\mathrm{x}-4}{1}=\frac{\mathrm{y}+7}{-2}=\frac{\mathrm{z}-8}{2}$, then find the distance between sides AB and CD . Hence, find the area of parallelogram ABCD .
Marking-scheme solution
$$l_{1}: \frac{\mathrm{x}}{1}=\frac{\mathrm{y}-1}{2}=\frac{\mathrm{z}-2}{3}=\lambda ; l_{2}: \frac{\mathrm{x}-1}{0}=\frac{\mathrm{y}}{-3}=\frac{\mathrm{z}-7}{2}=\mu
$$
any point on $\displaystyle l_{1}$ is $\displaystyle (\lambda, 2 \lambda+1,3 \lambda+2)$ & any point on $\displaystyle l_{2}$ is $\displaystyle (1,-3 \mu, 2 \mu+7)$
If $\displaystyle l_{1}$ and $\displaystyle l_{2}$ intersect,
$$\lambda=1,2 \lambda+1=-3 \mu \text { and } 3 \lambda+2=2 \mu+7 \Rightarrow \lambda=1 \text { and } \mu=-1
$$
Point of intersection of $\displaystyle l_{1}$ and $\displaystyle l_{2}$ is $\displaystyle (1,3,5)$.
Let d.r.'s of required line be $\displaystyle \langle a, b, c\rangle$. Then,
$$a+2 b+3 c=0 \text { and }-3 b+2 c=0 \Rightarrow \frac{a}{13}=\frac{b}{-2}=\frac{c}{-3}
$$
Required equation of line is $\displaystyle \frac{\mathrm{x}-1}{13}=\frac{\mathrm{y}-3}{-2}=\frac{\mathrm{z}-5}{-3}$
d.r's of CD are $\displaystyle \langle 1,-2,2\rangle$
∴ d.r's of AB are $\displaystyle <1,-2,2>$
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CBSE Class 12 Mathematics past-paper question from the 2024 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.