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Mathematics · 2022 · 3 marks
CBSE 2022 · Region 1 · Set 2 · Q10
Find the co-ordinates of the point on the line (x+2)/3=(y +1)/2=(z -3)/2 which is at a distance of 5 units from the point (1, 3, 3).
Find the co-ordinates of the point on the line $\displaystyle \frac{x+2}{3}=\frac{\mathrm{y}+1}{2}=\frac{\mathrm{z}-3}{2}$ which is at a distance of $\displaystyle 5$ units from the point ($\displaystyle 1$, $\displaystyle 3$, $\displaystyle 3$).
Marking-scheme solution
Let the required point on given line be ( \(\displaystyle 3 \lambda-2,2 \lambda-1,2 \lambda+3\) ) for some \(\displaystyle \lambda\). According to question
\[\begin{aligned}
& \sqrt{(3 \lambda-3)^{2}+(2 \lambda-4)^{2}+(2 \lambda)^{2}}=5 \\
& 17 \lambda^{2}-34 \lambda+25=25 \\
& 17 \lambda(\lambda-2)=0 \text { gives } \lambda=0, \lambda=2
\end{aligned}
\]
∴ Coordinates of required points are (-$\displaystyle 2$, -$\displaystyle 1$, $\displaystyle 3$), ($\displaystyle 4$, $\displaystyle 3$, $\displaystyle 7$)
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