CBSE 2024 · Region 4 · Set 1 · Q19 · 2 marks
(a)Which compound in the given pair would undergo $\displaystyle \mathrm{S}_{\mathrm{N}} 2$ reaction at a faster rate and why ? $\displaystyle \mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{I}$ and $\displaystyle \mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{Br}$(b)Arrange the following compounds in the increasing order of their boiling points : Butane, $\displaystyle 1$-Bromobutane, $\displaystyle 1$-Iodobutane, $\displaystyle 1$-Chlorobutane $\displaystyle \mathbf{1} \boldsymbol{\times} \mathbf{2}$
(a)
Which compound in the given pair would undergo $\displaystyle \mathrm{S}_{\mathrm{N}} 2$ reaction at a faster rate and why ? $\displaystyle \mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{I}$ and $\displaystyle \mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{Br}$
(b)
Arrange the following compounds in the increasing order of their boiling points : Butane, $\displaystyle 1$-Bromobutane, $\displaystyle 1$-Iodobutane, $\displaystyle 1$-Chlorobutane $\displaystyle \mathbf{1} \boldsymbol{\times} \mathbf{2}$
Marking-scheme solution
a) \(\displaystyle \mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{I}\); lodide is a better leaving group/ due to larger size of iodine.
b) Butane < $\displaystyle 1$ - Chlorobutane < $\displaystyle 1$- Bromobutane < $\displaystyle 1$ - lodobuatane.
Haloalkanes and HaloarenesChemical Reactions of Haloalkanes and HaloarenesUnderstandvery_short_answermedium
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CBSE Class 12 Chemistry past-paper question from the 2024board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.