SolveItNCERT · CBSE Boards

CBSE 2023 · Region 5 · Set 1 · Q33 · 5 marks

(i)
Why is boiling point of $\displaystyle 1$ M NaCl solution more than that of $\displaystyle 1$ M glucose solution ?
(ii)
A non-volatile solute 'X' (molar mass $\displaystyle =50 \mathrm{~g} \mathrm{~mol}^{-1}$ ) when dissolved in 78g of benzene reduced its vapour pressure to $\displaystyle 90$%. Calculate the mass of X dissolved in the solution.
(iii)
Calculate the boiling point elevation for a solution prepared by adding 10g of $\displaystyle \mathrm{MgCl}_{2}$ to 200g of water assuming $\displaystyle \mathrm{MgCl}_{2}$ is completely dissociated. ( $\displaystyle \mathrm{K}_{\mathrm{b}}$ for Water $\displaystyle =0.512 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}$, Molar mass $\displaystyle \mathrm{MgCl}_{2}=95 \mathrm{~g} \mathrm{~mol}^{-1}$ )

SolutionsColligative Properties and Determination of Molar MassApplylong_answerhard

More from Solutions

CBSE Class 12 Chemistry past-paper question from the 2023board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.