Henry's law constant for CO_2 in water is 1.67 × 10^8 Pa at 298 K. Calculate the number of moles of CO_2 in 540 g of soda water when packed under…

$$x_{\mathrm{CO_2}} = \frac{P_{\mathrm{CO_2}}}{K_{\mathrm{H}}}$$$$= \frac{3.34 \times 10^{5}}{1.67 \times 10^{8}}$$$$= 2 \times 10^{-3}$$$$2 \times 10^{-3} = \frac{n_{\mathrm{CO_2}}}{n_{\mathrm{CO_2}} + n_{\mathrm{H_2O}}}$$For a dilute solution,$$2 \times 10^{-3} = \frac{n_{\mathrm{CO_2}}}{n_{\mathrm{H_2O}}}$$$$n_{\mathrm{CO_2}} = \frac{540}{18} \times 2 \times 10^{-3}$$$$= 6 \times 10^{-2}\ \text{mol.}$$