CBSE 2026 · Region 5 · Set 1 · Q29 · 4 marks
Ethers are prepared by the dehydration of alcohols in presence of protic acids at $\displaystyle 413$ K. Symmetrical and unsymmetrical ethers can also be prepared by Williamson synthesis. This reaction involves $\displaystyle \mathrm{S}_{\mathrm{N}} 2$ attack of an alkoxide ion on primary alkyl halide. If a tertiary alkyl halide is used, elimination reaction occurs and an alkene is formed, no ether is formed. C - O bond in ethers are cleaved under drastic conditions with excess of HI. When unsymmetrical ethers react with HI, the alkyl halide is formed from smaller alkyl group. If one of the alkyl group is tertiary, the alkyl halide is formed from the tertiary alkyl group because tertiary alkyl carbocation is more stable than the primary carbocation. Cleavage of alkyl aryl ethers takes place at the alkyl-oxygen bond due to more stable aryl-oxygen bond. The order of reactivity of hydrogen halides is $\displaystyle \mathrm{HI}>\mathrm{HBr}>\mathrm{HCl}$. Aromatic ethers undergo electrophilic substitution reactions. The alkoxy group attached to the aromatic ring activates the ring towards electrophilic substitution and directs the incoming group to ortho- and para-positions. Answer the following questions :Complete the following equations :(ii)(b)(i)Write the names of alkyl halide and sodium alkoxide used to prepare tert-butyl ethyl ether.(ii)Anisole on reaction with HI gives phenol and $\displaystyle \mathrm{CH}_{3}-\mathrm{I}$ and not methanol and iodobenzene. Justify the statement.(c)Why is C - O - C bond angle in ethers slightly greater than tetrahedral angle ?
Ethers are prepared by the dehydration of alcohols in presence of protic acids at $\displaystyle 413$ K. Symmetrical and unsymmetrical ethers can also be prepared by Williamson synthesis. This reaction involves $\displaystyle \mathrm{S}_{\mathrm{N}} 2$ attack of an alkoxide ion on primary alkyl halide. If a tertiary alkyl halide is used, elimination reaction occurs and an alkene is formed, no ether is formed. C - O bond in ethers are cleaved under drastic conditions with excess of HI. When unsymmetrical ethers react with HI, the alkyl halide is formed from smaller alkyl group. If one of the alkyl group is tertiary, the alkyl halide is formed from the tertiary alkyl group because tertiary alkyl carbocation is more stable than the primary carbocation. Cleavage of alkyl aryl ethers takes place at the alkyl-oxygen bond due to more stable aryl-oxygen bond. The order of reactivity of hydrogen halides is $\displaystyle \mathrm{HI}>\mathrm{HBr}>\mathrm{HCl}$. Aromatic ethers undergo electrophilic substitution reactions. The alkoxy group attached to the aromatic ring activates the ring towards electrophilic substitution and directs the incoming group to ortho- and para-positions. Answer the following questions :
Complete the following equations :
(ii)
(b)(i)
Write the names of alkyl halide and sodium alkoxide used to prepare tert-butyl ethyl ether.
(ii)
Anisole on reaction with HI gives phenol and $\displaystyle \mathrm{CH}_{3}-\mathrm{I}$ and not methanol and iodobenzene. Justify the statement.
(c)
Why is C - O - C bond angle in ethers slightly greater than tetrahedral angle ?
Marking-scheme solution
(a)
(ii)
(b)
Ethyl halide and sodium tert-butoxide / C2H5X and (CH3)3C-O-Na
(ii)
Bond between O−C6H5 is stronger than the bond between O−CH3 due to resonance / Due
to sp2 hybridisation there is partial double bond character in O−C6H5.
(c)
Because of repulsion between two alkyl groups.
Alcohols, Phenols and EthersEthersUnderstandcase_studymedium
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CBSE Class 12 Chemistry past-paper question from the 2026board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.