CBSE 2023 · Region 1 · Set 1 · Q26 · 3 marks
(a)Differentiate between Ideal solution and Non-ideal solution.(b)$\displaystyle 30$ g of urea is dissolved in $\displaystyle 846$ g of water. Calculate the vapour pressure of water for this solution if vapour pressure of pure water at $\displaystyle 298$ K is $\displaystyle 23.8$ mm Hg.
(a)
Differentiate between Ideal solution and Non-ideal solution.
(b)
$\displaystyle 30$ g of urea is dissolved in $\displaystyle 846$ g of water. Calculate the vapour pressure of water for this solution if vapour pressure of pure water at $\displaystyle 298$ K is $\displaystyle 23.8$ mm Hg.
Marking-scheme solution
(a)
| Ideal Solution | Non-ideal solution |
| The solution obeys Raoult's law at all concentrations. | The solution does not obey Raoult's law. |
| \(\displaystyle \Delta\) Vmixing \(\displaystyle =0\) and \(\displaystyle \Delta \mathrm{H}_{\text {mixing }}=0\) | \(\displaystyle \Delta \mathrm{V}_{\text {mixing }} \neq 0\) and \(\displaystyle \Delta \mathrm{H}_{\text {mixing }} \neq 0\). |
(b) \(\displaystyle \frac{\mathrm{P}_{\mathrm{A}}^{\mathrm{o}}-\mathrm{P}_{\mathrm{A}}}{\mathrm{P}_{\mathrm{A}^{\mathrm{o}}}}=\frac{\dfrac{\mathrm{W}_{\mathrm{B}}}{\mathrm{M}_{\mathrm{B}}}}{\dfrac{\mathrm{W}_{\mathrm{B}}}{\mathrm{M}_{\mathrm{B}}}+\dfrac{\mathrm{W}_{\mathrm{A}}}{\mathrm{M}_{\mathrm{A}}}}\)
\[\text { or } 1-\frac{\mathrm{P}_{\mathrm{A}}}{23 \cdot 8}=\frac{\dfrac{30}{60}}{\dfrac{846}{18}+\dfrac{30}{60}}
\]
\[\mathrm{P}_{\mathrm{A}}=\frac{46.5}{47} \times 23.8=23.5 \mathrm{~mm} \mathrm{Hg} \quad \text { or } \quad \mathrm{P}_{\mathrm{A}}=\frac{47}{47.5} \times 23.8=23.5 \mathrm{~mm} \mathrm{Hg}
\]
.SolutionsIdeal and Non-ideal SolutionsApplyshort_answermedium
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CBSE Class 12 Chemistry past-paper question from the 2023board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.