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Chemistry · 2023 · 3 marks
CBSE 2023 · Region 1 · Set 2 · Q27
Complete the following reactions: 1 1/2+1 1/2=3 (a) CH_3 CH_2 CH_2 Br →[Δ] Alc. KOH ( A ) → HBr ( B )
Complete the following reactions: \[1 \frac{1}{2}+1 \frac{1}{2}=3 \]
(a)
$\displaystyle \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{Br} \xrightarrow[\Delta]{\text { Alc. } \mathrm{KOH}}(\mathrm{A}) \xrightarrow{\mathrm{HBr}}(\mathrm{B})$
Marking-scheme solution
(a)(A)
$\displaystyle =$ $\displaystyle \mathrm{CH_3\text{-}CH=CH_2}$,
(B)
$\displaystyle =$ 
(b)(A)
$\displaystyle =$ $\displaystyle \mathrm{CH_3-\underset{\overset{\textstyle|}{\textstyle\mathrm{OH}}}{CH}-CH_3}$ , i.e. \[\begin{array}{ccc} \mathrm{CH_3} - & \mathrm{CH} & - \mathrm{CH_3} \\ & | & \\ & \mathrm{OH} & \end{array}\]
(B)
$\displaystyle =$ $\displaystyle \mathrm{CH_3-\underset{\overset{\textstyle|}{\textstyle\mathrm{Cl}}}{CH}-CH_3}$ , i.e. \[\begin{array}{ccc} \mathrm{CH_3} - & \mathrm{CH} & - \mathrm{CH_3} \\ & | & \\ & \mathrm{Cl} & \end{array}\]
(B)
$\displaystyle =$ \[\begin{array}{ccc} \mathrm{CH_3} - & \mathrm{CH} & - \mathrm{CH_3} \\ & | & \\ \mathrm{CH_3} - & \mathrm{CH} & - \mathrm{CH_3} \end{array}\]
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