CBSE 2025 · Region 7 · Set 1 · Q25 · 3 marks
A compound (A) with molecular formula $\displaystyle \mathrm{C}_{4} \mathrm{H}_{9} \mathrm{I}$ which is a primary alkyl halide, reacts with alcoholic KOH to give compound (B). Compound (B) reacts with HI to give (C) which is an isomer of (A). When (A) reacts with Na metal in the presence of dry ether, it gives a compound (D), $\displaystyle \mathrm{C}_{8} \mathrm{H}_{18}$, which is different from the compound formed when n-butyl iodide reacts with sodium. Write the structures of (A), (B), (C) and (D). Write the chemical equation when compound (A) is reacted with alcoholic KOH.
Marking-scheme solution
A=
B=
C=
D=
$\displaystyle +\ \mathrm{KI}\ +\ \mathrm{H_2O}$
Haloalkanes and HaloarenesMethods of Preparation of HaloalkanesAnalyseshort_answerhard
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CBSE Class 12 Chemistry past-paper question from the 2025board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.