✓ Board-verified
Applied Mathematics · 2024 · 1 mark
CBSE 2024 · Central · Set 4 · Q20
Questions number 19 and 20 are Assertion and Reason based questions. Two statements are given, one labelled Assertion (A) and the other labelled…
Questions number $\displaystyle 19$ and $\displaystyle 20$ are Assertion and Reason based questions. Two statements are given, one labelled Assertion (A) and the other labelled Reason (R). Select the correct answer from the codes (A), (B), (C) and (D) as given below.
In a binomial distribution, $\displaystyle \mathrm{n}=200$ and $\displaystyle \mathrm{p}=0.04$. Taking Poisson distribution as an approximation to the binomial distribution :
Assertion (A): Mean of Poisson distribution = 8.
Reason (R): $\displaystyle \mathrm{P}(\mathrm{X}=4)=\frac{512}{3 \mathrm{e}^8}$.
Official answer
(B)
Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
More from Probability Distributions
- If for a Poisson variate X, P(X=k)=P(X=k+1), then the variance of X is:2024
- If ‘m’ is the mean of a Poisson distribution, then its variance is given by:2026
- The total area under a standard normal curve is:2026
- If a random variable X has the probability distribution P(X=x)= {k, if x=0; 2 k, if x=1 or 2; 0, otherwise,} then the value of k is2025
- A pair of dice is thrown two times. If X represents the number of doublets obtained, then the expectation of X is2025
- A fair coin is tossed twice and outcomes are noted. If the random variable X represents the number of heads that appeared in the experiment, then the…2024
- Let X be a discrete random variable, then the variance of X is::2026
- If X is a Poisson variable such that P(X=1)=2 P(X=2), then P(X=0) is:2023
CBSE Class 12 Applied Mathematics past-paper question from the 2024 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.