Maximise z =300 x +190 y subject to constraints: x + y ≤ 24, 2 x + y ≤ 32, x ≥ 0, y ≥ 0.

Maximise $\displaystyle \mathrm{z}=300 \mathrm{x}+190 \mathrm{y}$ subject to constraints : $\displaystyle \mathrm{x}+\mathrm{y} \leq 24,$ $\displaystyle 2 \mathrm{x}+\mathrm{y} \leq 32,$ $\displaystyle \mathrm{x} \geq 0, \mathrm{y} \geq 0.$