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Applied Mathematics · 2024 · 2 marks
CBSE 2024 · Central · Set 4 · Q21
(a) If A = [1, 0; -1, 7], find the value of k such that A^2-8 A + kI =0.
If $\displaystyle \mathrm{A}=\left[\begin{array}{cc}1 & 0 \\ -1 & 7\end{array}\right]$, find the value of k such that $\displaystyle \mathrm{A}^2-8 \mathrm{~A}+\mathrm{kI}=0$.
If $\displaystyle \left[\begin{array}{cc}\mathrm{x}-\mathrm{y} & 2 \mathrm{x}+\mathrm{z} \\ 2 \mathrm{x}-\mathrm{y} & 3 \mathrm{z}+\mathrm{w}\end{array}\right]=\left[\begin{array}{cc}-1 & 5 \\ 0 & 13\end{array}\right]$, find the values of x, y, z and w.
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CBSE Class 12 Applied Mathematics past-paper question from the 2024 board exam. Where our answers come from.