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Applied Mathematics · 2026 · 1 mark
CBSE 2026 · Central · Set 4 · Q7
If x = t^2 and y = t^3, then (d^2 y)/(dx^2) is equal to:
If $\displaystyle \mathrm{x}=\mathrm{t}^2$ and $\displaystyle \mathrm{y}=\mathrm{t}^3$, then $\displaystyle \frac{\mathrm{d}^2 \mathrm{y}}{\mathrm{dx}^2}$ is equal to :
Official answer
(B)
$\displaystyle \frac{3}{4 \mathrm{t}}$
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