✓ Board-verified
Science · 2024 · 5 marks
CBSE 2024 · Region 3 · Set 1 · Q36
(a) (i) Draw a ray diagram to show the path of the refracted ray in each of the following cases: A ray of light incident on a concave lens (1)…
(a)(i)
Draw a ray diagram to show the path of the refracted ray in each of the following cases : A ray of light incident on a concave lens
(1)
parallel to its principal axis, and
(2)
is directed towards its principal focus.
(ii)
A $\displaystyle 4$ cm tall object is placed perpendicular to the principal axis of convex lens of focal length $\displaystyle 24$ cm. The distance of object from the lens is $\displaystyle 16$ cm. Find the position and size of image formed.
OR 36. (b) (i) Draw a ray diagram to show the path of the reflected ray in each of the following cases : A ray of light incident on a convex mirror
(1)
parallel to its principal axis, and
(2)
is directed towards its principal focus
(ii)
A $\displaystyle 1.5$ cm tall candle flame is placed perpendicular to the principal axis of a concave mirror of focal length $\displaystyle 12$ cm. If the distance of the flame from the pole of the mirror is $\displaystyle 18$ cm, use mirror formula to determine the position and size of the image formed.
Marking-scheme solution
(a) (i)
(1)
Fig.9.13(b)-Page-$\displaystyle 153$, NCERT.
Fig.9.14(b)-Page-$\displaystyle 154$, NCERT.
Fig.9.13(b)-Page-$\displaystyle 153$, NCERT.
Fig.9.14(b)-Page-$\displaystyle 154$, NCERT.(ii) Given \(\displaystyle u=-16 \mathrm{~cm}, \mathrm{f}=+24 \mathrm{~cm}, \mathrm{~h}=4 \mathrm{~cm}\)
\[\begin{aligned}
& \text { Formula used } \frac{1}{v}-\frac{1}{u}=\frac{1}{f} \\
& \qquad \frac{1}{v}-\frac{1}{(-16)}=\frac{1}{+24} \\
& \frac{1}{v}=\frac{-1}{48}
\end{aligned}
\]
(ii)
Here \(\displaystyle \mathrm{f}=-12 \mathrm{~cm}, u=-18 \mathrm{~cm}, v=?, \mathrm{~h}=1 \cdot 5 \mathrm{~cm}, \mathrm{~h}^{\prime}=\) ? Mirror formula \(\displaystyle \frac{1}{v}+\frac{1}{u}=\frac{1}{f}\)
\[\begin{aligned}
\therefore \frac{1}{v} & =\frac{1}{f}-\frac{1}{u} \\
& =\frac{1}{-12 \mathrm{~cm}}-\frac{1}{-18 \mathrm{~cm}} \\
& =\frac{-1}{36}
\end{aligned}
\]
All Light - Reflection and Refraction questions2024 question paperNCERT solutions: Light - Reflection and RefractionPractice Light - Reflection and Refraction →
More from Light - Reflection and Refraction
- With the help of above given ray diagram, calculate the angle of refraction. Given that the refractive index of Medium 2 with respect to Medium 1 is…2026
- A student wants to obtain an erect image of an object using a concave mirror of 10 cm focal length. What will be the distance of the object from…2023
- An object is kept at a distance of 1m from a lens of power+2D: (i) Identify the type of lens. (ii) Calculate its focal length and distance of the…2023
- If the absolute refractive indices of two media X and Y are 6/5 and 4/3 respectively, then the refractive index of Y with respect to X will be:2025
- A student wants to project the image of a candle flame on a screen 60 cm in front of a mirror by keeping the candle at a distance of 15 cm from its…2023
- An object is placed in front of a concave mirror of focal length 12 cm. If distance of the object from the pole of the mirror is 8 cm, then use…2024
- (i) "In refraction of light through a rectangular glass slab, the emergent ray is always parallel to the direction of the incident ray." Why? Explain…2025
- The above ray diagram is to show image formation by a reflecting telescope. Reflecting telescope revolutionized our way of looking into the sky.…2026
CBSE Class 10 Science past-paper question from the 2024 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.