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Science · 2022 · 2 marks
CBSE 2022 · Region 2 · Set 2 · Q6
A part of modern periodic table is given below. On its basis, answer the following questions: $\displaystyle \frac{1}{2} \times 4=2$ Group No. → 2 2 2 2 2 2 2 2 Period ↓ $\displaystyle 2$ A B $\displaystyle 3$ E D F C
(a)Write the molecular formula of the compound formed by the combination :(i)A and F(ii)E and B(b)Which of the element is a(i)Noble gas(ii)Metalloid
A part of modern periodic table is given below. On its basis, answer the following questions: $\displaystyle \frac{1}{2} \times 4=2$
| Group No. → | 2 | 2 | 2 | 2 | 2 | 2 | 2 | 2 |
| Period ↓ | ||||||||
| $\displaystyle 2$ | A | B | ||||||
| $\displaystyle 3$ | E | D | F | C |
(a)
Write the molecular formula of the compound formed by the combination :
(i)
A and F
(ii)
E and B
(b)
Which of the element is a
(i)
Noble gas
(ii)
Metalloid
Marking-scheme solution
(a) (i) \(\displaystyle \mathrm{AF}_{2}\) (ii) \(\displaystyle \mathrm{E}_{2} \mathrm{~B}\)
(b) (i) C (ii) D
CBSE Class 10 Science past-paper question from the 2022board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.