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Science · 2023 · 5 marks
CBSE 2023 · Region 5 · Set 1 · Q34
A neutral organic compound 'X' (Molecular formula $\displaystyle \mathrm{C}_{2} \mathrm{H}_{6} \mathrm{O}$ ) on reacting with acidified $\displaystyle \mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}$ gives an organic compound 'Y' which is acidic in nature. 'X' reacts with 'Y' on warming in the presence of conc. $\displaystyle \mathrm{H}_{2} \mathrm{SO}_{4}$ to give a sweet smelling compound 'Z'.(i)Identify 'X', 'Y' and 'Z'.(ii)Write the chemical equations for the reactions in the conversion of ($\displaystyle 1$) 'X' to 'Y' and ($\displaystyle 2$) 'X' to 'Z'.(iii)State the role of ($\displaystyle 1$) acidified $\displaystyle \mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}$ in the conversion of 'X' to 'Y' and ($\displaystyle 2$) conc. $\displaystyle \mathrm{H}_{2} \mathrm{SO}_{4}$ in the reaction of 'X' and 'Y'.(iv)Name the reaction which occurs when 'Z' reacts with an alkali.Carry out the following conversions, stating the condition(s) for each :(i)Ethanol ⟶ Ethene(ii)Ethene ⟶ Ethane(iii)Ethane ⟶ Chloroethane(iv)Ethanol ⟶ Ethanoic acid(v)Ethanoic acid ⟶ Ethyl ethanoate
A neutral organic compound 'X' (Molecular formula $\displaystyle \mathrm{C}_{2} \mathrm{H}_{6} \mathrm{O}$ ) on reacting with acidified $\displaystyle \mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}$ gives an organic compound 'Y' which is acidic in nature. 'X' reacts with 'Y' on warming in the presence of conc. $\displaystyle \mathrm{H}_{2} \mathrm{SO}_{4}$ to give a sweet smelling compound 'Z'.
(i)
Identify 'X', 'Y' and 'Z'.
(ii)
Write the chemical equations for the reactions in the conversion of ($\displaystyle 1$) 'X' to 'Y' and ($\displaystyle 2$) 'X' to 'Z'.
(iii)
State the role of ($\displaystyle 1$) acidified $\displaystyle \mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}$ in the conversion of 'X' to 'Y' and ($\displaystyle 2$) conc. $\displaystyle \mathrm{H}_{2} \mathrm{SO}_{4}$ in the reaction of 'X' and 'Y'.
(iv)
Name the reaction which occurs when 'Z' reacts with an alkali.
Carry out the following conversions, stating the condition(s) for each :
(i)
Ethanol ⟶ Ethene
(ii)
Ethene ⟶ Ethane
(iii)
Ethane ⟶ Chloroethane
(iv)
Ethanol ⟶ Ethanoic acid
(v)
Ethanoic acid ⟶ Ethyl ethanoate
Marking-scheme solution
(a) (i) \(\displaystyle \mathrm{X}: \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH} /\) Ethyl alcohol / Ethanol
\(\displaystyle \mathrm{Y}: \mathrm{CH}_{3} \mathrm{COOH} /\) Acetic acid \(\displaystyle /\) Ethanoic acid
\(\displaystyle \mathrm{Z}: \mathrm{CH}_{3} \mathrm{COOC}_{2} \mathrm{H}_{5} /\) Ethyl ethanoate / Ethyl acetate
(1) \(\displaystyle \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH} \xrightarrow{\text { Acidified } \mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}} \mathrm{CH}_{3} \mathrm{COOH}\)
(2) \(\displaystyle \mathrm{CH}_{3} \mathrm{COOH}+\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH} \xrightarrow{\text { Conc. } \mathrm{H}_{2} \mathrm{SO}_{4}} \mathrm{CH}_{3} \mathrm{COOC}_{2} \mathrm{H}_{5}+\mathrm{H}_{2} \mathrm{O}\)
(iii) ($\displaystyle 1$) Oxidising agent / provides oxygen
(2) Dehydrating agent / helps in removing water
(iv) Saponification reaction
OR
(b) (i) \(\displaystyle \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH} \xrightarrow[443 \mathrm{~K}]{\text { Conc. } \mathrm{H}_{2} \mathrm{SO}_{4}} \mathrm{C}_{2} \mathrm{H}_{4}+\mathrm{H}_{2} \mathrm{O}\)
(ii) \(\displaystyle \mathrm{H}_{2} \mathrm{C}=\mathrm{CH}_{2} \xrightarrow[N i / P d]{\mathrm{H}_{2}} \mathrm{CH}_{3}-\mathrm{CH}_{3}\)
(iii) \(\displaystyle \mathrm{C}_{2} \mathrm{H}_{6}+\mathrm{Cl}_{2} \xrightarrow{\text { Sunlight }} \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}+\mathrm{HCl}\)
(iv) \(\displaystyle \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH} \xrightarrow[\text { Acidified } \mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}]{\text { Alkaline } \mathrm{KMnO}_{4}} \mathrm{CH}_{3} \mathrm{COOH}\)
(v) \(\displaystyle \mathrm{CH}_{3} \mathrm{COOH}+\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH} \xrightarrow{\text { Acid }} \mathrm{CH}_{3} \mathrm{COOC}_{2} \mathrm{H}_{5}+\mathrm{H}_{2} \mathrm{O}\)
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CBSE Class 10 Science past-paper question from the 2023board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.