The sum of the first three terms of an A.P. is 33. If the product of first and third term exceeds the second term by $\displaystyle 29$, find the A.P.

Let three terms of AP be \(\displaystyle a-d, a, a+d\) \[\begin{aligned} & \text { Sum }=33 \Rightarrow a-d+a+a+d=33 \\ & 3 a=33 \Rightarrow a=11 \end{aligned} \] When \(\displaystyle d=9, a=11\); A.P. is \(\displaystyle 2,11,20, \ldots\) When \(\displaystyle d=-9, a=11\); A.P. is $\displaystyle 20$, $\displaystyle 11$, 2...