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Mathematics · 2026 · 5 marks
CBSE 2026 · Region 1 · Set 1 · Q35
The mean of the following frequency distribution is $\displaystyle 35$ . Find the values of $\displaystyle x$ and $\displaystyle y$, if the sum of frequencies is $\displaystyle 25$ :

Marking-scheme solution
lathematics_041_30/$\displaystyle 1$/1_2025-$\displaystyle 26$
\[\sum f_{i}=25 \Rightarrow x+y=8
\]
$\displaystyle \operatorname{Mean}(\bar{x})=\frac{605+15 x+45 y}{25}=35$
\[\Rightarrow 15 x+45 y=270 \text { or } x+3 y=18
\]Solving (i) and (ii), we get $\displaystyle x=3, y=5$SECTION - E
Question numbers $\displaystyle 36$ to $\displaystyle 38$ are Case Study Based questions, carrying $\displaystyle 4$ marks each
| Class Interval | Frequency $\displaystyle \left(f_{i}\right)$ | $\displaystyle x_{i}$ | $\displaystyle f_{i} x_{i}$ |
| $\displaystyle 0$-$\displaystyle 10$ | $\displaystyle 1$ | $\displaystyle 5$ | $\displaystyle 5$ |
| $\displaystyle 10$-$\displaystyle 20$ | $\displaystyle x$ | $\displaystyle 15$ | $\displaystyle 15 x$ |
| $\displaystyle 20$-$\displaystyle 30$ | $\displaystyle 5$ | $\displaystyle 25$ | $\displaystyle 125$ |
| $\displaystyle 30$-$\displaystyle 40$ | $\displaystyle 7$ | $\displaystyle 35$ | $\displaystyle 245$ |
| $\displaystyle 40$-$\displaystyle 50$ | $\displaystyle y$ | $\displaystyle 45$ | $\displaystyle 45 y$ |
| $\displaystyle 50$-$\displaystyle 60$ | $\displaystyle 3$ | $\displaystyle 55$ | $\displaystyle 165$ |
| $\displaystyle 60$-$\displaystyle 70$ | $\displaystyle 1$ | $\displaystyle 65$ | $\displaystyle 65$ |
| Total | $\displaystyle 25$ | $\displaystyle 605+15 x+45 y$ |
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CBSE Class 10 Mathematics past-paper question from the 2026board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.