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Mathematics · 2022 · 3 marks
CBSE 2022 · Region 2 · Set 1 · Q9
The mean of the following frequency distribution is 25. Find the value of f. Class : $\displaystyle 0$-$\displaystyle 10$ $\displaystyle 10$-$\displaystyle 20$ $\displaystyle 20$-$\displaystyle 30$ $\displaystyle 30$-$\displaystyle 40$ $\displaystyle 40$-$\displaystyle 50$ Frequency : $\displaystyle 5$ $\displaystyle 18$ $\displaystyle 15$ f $\displaystyle 6$
Find the mean of the following data using assumed mean method : Class : $\displaystyle 0$-$\displaystyle 5$ $\displaystyle 5$-$\displaystyle 10$ $\displaystyle 10$-$\displaystyle 15$ $\displaystyle 15$-$\displaystyle 20$ $\displaystyle 20$-$\displaystyle 25$ Frequency : $\displaystyle 8$ $\displaystyle 7$ $\displaystyle 10$ $\displaystyle 13$ $\displaystyle 12$
The mean of the following frequency distribution is 25. Find the value of f.
| Class : | $\displaystyle 0$-$\displaystyle 10$ | $\displaystyle 10$-$\displaystyle 20$ | $\displaystyle 20$-$\displaystyle 30$ | $\displaystyle 30$-$\displaystyle 40$ | $\displaystyle 40$-$\displaystyle 50$ |
| Frequency : | $\displaystyle 5$ | $\displaystyle 18$ | $\displaystyle 15$ | f | $\displaystyle 6$ |
Find the mean of the following data using assumed mean method :
| Class : | $\displaystyle 0$-$\displaystyle 5$ | $\displaystyle 5$-$\displaystyle 10$ | $\displaystyle 10$-$\displaystyle 15$ | $\displaystyle 15$-$\displaystyle 20$ | $\displaystyle 20$-$\displaystyle 25$ |
| Frequency : | $\displaystyle 8$ | $\displaystyle 7$ | $\displaystyle 10$ | $\displaystyle 13$ | $\displaystyle 12$ |
Marking-scheme solution
Class & \(\displaystyle x\) & \(\displaystyle f\) & fx
$\displaystyle 0$-$\displaystyle 10$ & $\displaystyle 5$ & $\displaystyle 5$ & $\displaystyle 25$
$\displaystyle 10$-$\displaystyle 20$ & $\displaystyle 15$ & $\displaystyle 18$ & $\displaystyle 270$
$\displaystyle 20$-$\displaystyle 30$ & $\displaystyle 25$ & $\displaystyle 15$ & $\displaystyle 375$
$\displaystyle 30$-$\displaystyle 40$ & $\displaystyle 35$ & \(\displaystyle f\) & 35f
$\displaystyle 40$-$\displaystyle 50$ & $\displaystyle 45$ & $\displaystyle 6$ & $\displaystyle 270$
& & \(\displaystyle 44+f\) & \(\displaystyle 940+35 f\)\[\begin{gathered}
\bar{x}=12 \cdot 5+\frac{70}{50} \\
=13 \cdot 9
\end{gathered}
\]
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