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Mathematics · 2024 · 5 marks
CBSE 2024 · Region 4 · Set 3 · Q32
The following distribution shows the daily pocket allowance of children of a locality. The mean daily pocket allowance is ₹ $\displaystyle 36 \cdot 10$. Find the missing frequency, f. Daily pocket allowance (in ₹) $\displaystyle 20$-$\displaystyle 25$ $\displaystyle 25$-$\displaystyle 30$ $\displaystyle 30$-$\displaystyle 35$ $\displaystyle 35$-$\displaystyle 40$ $\displaystyle 40$-$\displaystyle 45$ $\displaystyle 45$-$\displaystyle 50$ $\displaystyle 50$-$\displaystyle 55$ Number of children $\displaystyle 7$ $\displaystyle 6$ $\displaystyle 9$ $\displaystyle 13$ f $\displaystyle 5$ $\displaystyle 4$
| Daily pocket allowance (in ₹) | $\displaystyle 20$-$\displaystyle 25$ | $\displaystyle 25$-$\displaystyle 30$ | $\displaystyle 30$-$\displaystyle 35$ | $\displaystyle 35$-$\displaystyle 40$ | $\displaystyle 40$-$\displaystyle 45$ | $\displaystyle 45$-$\displaystyle 50$ | $\displaystyle 50$-$\displaystyle 55$ |
| Number of children | $\displaystyle 7$ | $\displaystyle 6$ | $\displaystyle 9$ | $\displaystyle 13$ | f | $\displaystyle 5$ | $\displaystyle 4$ |
Marking-scheme solution
| Daily pocket allowance (in ₹) | Number of children \(\displaystyle \left(f_{i}\right)\) | \(\displaystyle x_{i}\) | \(\displaystyle x_{i} f_{i}\) |
| $\displaystyle 20$-$\displaystyle 25$ | $\displaystyle 7$ | $\displaystyle 22.5$ | $\displaystyle 157.5$ |
| $\displaystyle 25$-$\displaystyle 30$ | $\displaystyle 6$ | $\displaystyle 27.5$ | $\displaystyle 165$ |
| $\displaystyle 30$-$\displaystyle 35$ | $\displaystyle 9$ | $\displaystyle 32.5$ | $\displaystyle 292.5$ |
| $\displaystyle 35$-$\displaystyle 40$ | $\displaystyle 13$ | $\displaystyle 37.5$ | $\displaystyle 487.5$ |
| $\displaystyle 40$-$\displaystyle 45$ | f | $\displaystyle 42.5$ | $\displaystyle 42.5$ f |
| $\displaystyle 45$-$\displaystyle 50$ | $\displaystyle 5$ | $\displaystyle 47.5$ | $\displaystyle 237.5$ |
| $\displaystyle 50$-$\displaystyle 55$ | $\displaystyle 4$ | $\displaystyle 52.5$ | $\displaystyle 210.0$ |
| Total | \(\displaystyle 44+\mathrm{f}\) | $\displaystyle 1550$ + $\displaystyle 42.5$ f |
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