Prove that a parallelogram circumscribing a circle is a rhombus.

\[\begin{aligned} & \text { 2. Since } D E \text { is a straight line therefore } \angle A \\ & \therefore d^{2}=A C^{2}+B C^{2}=(100)^{2}+(40 \sqrt{3})^{2} \\ & \Rightarrow d=\sqrt{14800} \text { or } 20 \sqrt{37} \mathrm{~m} \end{aligned} \] 2. \[\begin{aligned} & \text { Canvas used }=1650+30=1680 \mathrm{~m}^{2} \\ & \begin{aligned} \therefore \text { cost of canvas used } & =200 \times 1680 \\ & =₹ 3,36,000 \end{aligned} \end{aligned} \]