Medical check-up was carried out for 35 students of a class and their weights were recorded as follows: Find the difference between the mean weight…

Weight (in kg)	Number of Students ( \(\displaystyle f_{\mathrm{i}}\) )	\(\displaystyle x_{\mathrm{i}}\)	\(\displaystyle u_{\mathrm{i}=\frac{x_{i}-45}{2}}\)	\(\displaystyle f_{\mathrm{i}} u_{\mathrm{i}}\)	\(\displaystyle c f\)
$\displaystyle 38$-$\displaystyle 40$	$\displaystyle 3$	$\displaystyle 39$	-$\displaystyle 3$	-$\displaystyle 9$	$\displaystyle 3$
$\displaystyle 40$-$\displaystyle 42$	$\displaystyle 2$	$\displaystyle 41$	-$\displaystyle 2$	-$\displaystyle 4$	$\displaystyle 5$
$\displaystyle 42$-$\displaystyle 44$	$\displaystyle 4$	$\displaystyle 43$	-$\displaystyle 1$	-$\displaystyle 4$	$\displaystyle 9$
$\displaystyle 44$-$\displaystyle 46$	$\displaystyle 5$	\(\displaystyle 45=\mathrm{a}\)	$\displaystyle 0$	$\displaystyle 0$	$\displaystyle 14$
$\displaystyle 46$-$\displaystyle 48$	$\displaystyle 14$	$\displaystyle 47$	$\displaystyle 1$	$\displaystyle 14$	$\displaystyle 28$
$\displaystyle 48$-$\displaystyle 50$	$\displaystyle 4$	$\displaystyle 49$	$\displaystyle 2$	$\displaystyle 8$	$\displaystyle 32$
$\displaystyle 50$-$\displaystyle 52$	$\displaystyle 3$	$\displaystyle 51$	$\displaystyle 3$	$\displaystyle 9$	$\displaystyle 35$
Total	$\displaystyle 35$			$\displaystyle 14$

\(\displaystyle \frac{\mathbf{1}}{\mathbf{2}}\) ∴ Mean weight is $\displaystyle 45.8$ kg Median Class is $\displaystyle 46$-$\displaystyle 48$ \[\begin{aligned} \text { Median } & =46+\frac{\dfrac{35}{2}-14}{14} \times 2 \\ & =46.5 \end{aligned} \] ∴ Median weight is $\displaystyle 46.5$ kg Difference of mean weight and median weight \(\displaystyle =46.5-45.8=0.7 \mathrm{~kg}\)