CBSE 2025 · Region 1 · Set 1 · Q16 · 1 mark
In the given figure, PA is a tangent from an external point P to a circle with centre O . If $\displaystyle \angle \mathrm{POB}=115^{\circ}$, then $\displaystyle \angle \mathrm{APO}$ is equal to :
Official answer
From CBSE’s own marking scheme for this paper.
(A)
$\displaystyle 25$°
CirclesTangent to a CircleApplymcqmedium
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CBSE Class 10 Mathematics past-paper question from the 2025board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.