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Mathematics · 2026 · 4 marks
CBSE 2026 · Region 1 · Set 1 · Q36
In a potato race, a bucket is placed at the starting point, which is $\displaystyle 5$ m from the first potato. The other potatoes are arranged $\displaystyle 3$ m apart in a straight line, with a total of $\displaystyle 10$ potatoes, as shown in the figure :
A competitor starts from the bucket, picks up the nearest potato, runs back to the bucket to drop it in, then returns to pick up the next potato. This process continues until all the potatoes are in the bucket. Based on the above information, answer the following questions :(i)What is the distance covered to pick up the first potato and drop it in bucket ?(ii)What is the distance covered to pick up the second potato and drop it in bucket ?(iii)What is the total distance the competitor has to run ?If average speed of competitor is $\displaystyle 5$ m/s, then find the average time taken by competitor to put all the potatoes in the bucket.
In a potato race, a bucket is placed at the starting point, which is $\displaystyle 5$ m from the first potato. The other potatoes are arranged $\displaystyle 3$ m apart in a straight line, with a total of $\displaystyle 10$ potatoes, as shown in the figure :
A competitor starts from the bucket, picks up the nearest potato, runs back to the bucket to drop it in, then returns to pick up the next potato. This process continues until all the potatoes are in the bucket. Based on the above information, answer the following questions :
(i)
What is the distance covered to pick up the first potato and drop it in bucket ?
(ii)
What is the distance covered to pick up the second potato and drop it in bucket ?
(iii)
What is the total distance the competitor has to run ?
If average speed of competitor is $\displaystyle 5$ m/s, then find the average time taken by competitor to put all the potatoes in the bucket.
Marking-scheme solution
(i) Required distance for the first potato \(\displaystyle =5+5=10 \mathrm{~m}\)
(ii) Required distance for the second potato \(\displaystyle =8+8=16 \mathrm{~m}\)
(iii) (a) Distances covered form an A.P. with \(\displaystyle a=10\) and \(\displaystyle d=6\)
\[\begin{aligned}
\therefore S_{10} & =\frac{10}{2}[2 \times 10+9 \times 6] \\
& =5 \times 74=370 \mathrm{~m}
\end{aligned}
\]
OR
(iii) (b) Distances covered form an A.P. with \(\displaystyle a=10\) and \(\displaystyle d=6\)
\[\begin{aligned}
& \begin{aligned}
\therefore S_{10} & =\frac{10}{2}[2 \times 10+9 \times 6] \\
& =5 \times 74=370 \mathrm{~m}
\end{aligned} \\
& \text { Time }=\frac{370}{5}=74 \text { seconds }
\end{aligned}
\]
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CBSE Class 10 Mathematics past-paper question from the 2026board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.